“2018年IAO理论低年组第1题-水银镜面”的版本间的差异

来自astro-init
英文解答
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===英文题目===
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===原文题目===
 
'''Mercury mirror.''' As you know. If one rotates a vessel with mercury, its surface will take a parabolic form. A kiquid mirror obtained in this wan can be used as the main mirror of a telescope. The Polar Bear-astronomer living in the Arctic decided to use this idea and build such a telescope exactly at the Norht Pole, and use the daile revolution of the Earth as the rotation mechanism so that the main mirror would have a long focal length.
 
'''Mercury mirror.''' As you know. If one rotates a vessel with mercury, its surface will take a parabolic form. A kiquid mirror obtained in this wan can be used as the main mirror of a telescope. The Polar Bear-astronomer living in the Arctic decided to use this idea and build such a telescope exactly at the Norht Pole, and use the daile revolution of the Earth as the rotation mechanism so that the main mirror would have a long focal length.
  

2019年9月13日 (五) 08:30的版本

原文题目

Mercury mirror. As you know. If one rotates a vessel with mercury, its surface will take a parabolic form. A kiquid mirror obtained in this wan can be used as the main mirror of a telescope. The Polar Bear-astronomer living in the Arctic decided to use this idea and build such a telescope exactly at the Norht Pole, and use the daile revolution of the Earth as the rotation mechanism so that the main mirror would have a long focal length.

1.1. Is tge Polar Bear idea feasible? (Write "Yes" or "No"in English.)If yes, then find the focal length of the resulting liquid mirror, and if not, prove your conclusion by doing the necessary calculations and drawings.

1.2. Include an artistic picture with an image of the Bear-astronomer, engaged in the implementation of his project.

英文解答

Mercury mirror. Imagine rotating mercury. At each point, the normal to its surface will be directed at an angle γ =ω2r/g to the vertical, where ω is the angular velocity of rotation of mercury, r is the distance from the axis of rotation, g is the gravity acceleraton, If the direction of the vertical(vector g) is fixed, then this angle γ is related to the radius of curvature R of the liquid mirror as γ = r/R. From these two equations we get:

$$R = g/{\omega}^2 = gT^2/4{\pi}^2.$$

Substituting the values g = 9.8 m/s2 and T = 86164s, we get:

$$R \approx 1.84{\cdot}10^9m = 1.84\ million\ km.$$

The focal lenght of sucn a mirror would be:

$$F = R/2 = R/2 = gT^2/8{\pi}^2 \approx 0.92{\cdot}10^9 m = 920\ thousand\ km.$$

But ... The result would be true for a flat Earth. The condition "if the direction of the vertical is the Pole, the direction of the vertical changes 300 times faster (the Earth only reduces the curvature of the liquid surface at the pole by 1/300. The mirror designed by the Bear will be convex, its curvature will be exactly the same as the curvature of the Arctic Ocean.

Thus, the correct answer is "NO", the idea of PolarBear is impracticable